Explanation:
(a) An isochoric process is defined as the process in which volume of a system remains constant.
For example, an air conditioner follows an isochoric process.
(b) As pressure and temperature can change in an isochoric process but volume will remain the same.
Hence, heat can also be exchanged in an isochoric process. Whereas in an adiabatic process heat remains 0. Therefore, it means the in adiabatic process there occurs no exchange of heat between the system and its surrounding.
(c) It is given that V = 100 L = 0.1 [tex]m^{3}[/tex] (as 1 L = 0.001 [tex]m^{3}[/tex])
[tex]P_{1}[/tex] = [tex]10 \times 10^{6} Pa[/tex]
[tex]P_{2}[/tex] = [tex]15 \times 10^{6} Pa[/tex]
Relation between work, pressure and volume is as follows.
W = [tex]\Delta PV[/tex]
= PdV + VdP
= 0 + 0.1 [tex]m^{3} (15 - 10) \times 10^{6}[/tex]
(Since V = constant so, dV = 0)
= [tex]5 \times 10^{5} J[/tex]
Thus, we can conclude that work done is [tex]5 \times 10^{5} J[/tex].