Answer:
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
Explanation:
[tex]\frac{(y+3)}{2} = \frac{b}{(x-2)}[/tex]
Taking natural logarithm on both the sides:
[tex]\ln [(y+3)]-\ln[2]=\ln [b]-\ln [(x-2)][/tex]
[tex]\ln [(y+3)]=\ln[2]+\ln [b]-\ln [(x-2)][/tex]
[tex]\ln [(y+3)]=\ln {[2\times b]-\ln [(x-2)][/tex]
Slope intercept form is generally given as:
[tex]y=mx+c[/tex]
m = slope, c = intercept on y axis or vertical axis
On rearranging equation:
[tex]\ln [(y+3)]=(-1)\times \ln [(x-2)]+\ln {2b}[/tex]
y = ln [(y+3)], x = ln [(x-2)], m=-1 , c = ln 2b
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
