Respuesta :
Answer: The molarity of sulfuric acid solution is 2.3 M
Explanation:
The relationship between specific gravity and density of a substance is given as:
[tex]\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}[/tex]
Specific gravity of sulfuric acid solution = 1.13
Density of water = 1.00 g/mL
Putting values in above equation we get:
[tex]1.13=\frac{\text{Density of sulfuric acid solution}}{1.00g/mL}\\\\\text{Density of sulfuric acid solution}=(1.13\times 1.00g/mL)=1.13g/mL[/tex]
We are given:
20% (m/m) sulfuric acid solution. This means that 20 g of sulfuric acid is present in 100 g of solution
- To calculate volume of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of solution = 1.13 g/mL
Mass of Solution = 100 g
Putting values in above equation, we get:
[tex]1.13g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.13g/mL}=88.5mL[/tex]
- To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Mass of solute (sulfuric acid) = 20 g
Molar mass of sulfuric acid = 98 g/mol
Volume of solution = 88.5 mL
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{20g\times 1000}{98g/mol\times 88.5mL}\\\\\text{Molarity of solution}=2.3M[/tex]
Hence, the molarity of sulfuric acid solution is 2.3 M
