Answer:
(a) The amount of O2 needed is 2.67 pounds.
(b) The volume required is 847,509 litres.
(c) The heat given off as a result of the combustion to CO2 is 393.5 kJ.
Explanation:
For a complete combustion of C to C02(g)
[tex]C+O_{2} \rightarrow CO_{2}[/tex]
(a) The molecular mass of O2 is 32 g/mol and the molecular mass of C is 12 g/mol.
We need 1 mol O2 to burn 1 mol of C.
If we need 32 g of O2 to burn 12 g of C, to burn 1 pound of pure carbon charcoal we need (32/12)*1=2.67 pounds of O2.
(b) The density of O2, at atmospheric conditions, is 1.429 g/l. The volume of 2.67 pounds of O2 is
[tex]V=M/\rho=(2.67 lb)*(\frac{1 l}{1.429 g})*(\frac{453,592 g}{1lb}) =\frac{1,211,090}{1.429}= 847,509 l[/tex]
(c) To calculate the heat of the reaction, we have to look up in the Table of Standard Enthalpy of Formation Values and compute the following equation
[tex]\Delta H_{reaction}^{o}=\sum\Delta H_{f}^{o} (products)-\sum\Delta H_{f}^{o}(reactants)\\\\\Delta H_{reaction}^{o}=\Delta H_{f CO_{2}}^{o}-(\Delta H_{fO_{2}}^{o}+\Delta H_{fC}^{o})\\\\\Delta H_{reaction}^{o}=(1 mol) *(-393.5 kJ/mol)-((1mol)*(0 kJ/mol)+(1mol)*(0 kJ/mol))\\\\\Delta H_{reaction}^{o}=-393.5 kJ[/tex]
The heat given off as a result of the combustion to CO2 is 393.5 kJ.