Respuesta :

Explanation:

The given data is as follows.

            mass of gasoline = 595.0 lb

            volume of gasoline = [tex]14.0 ft^{3}[/tex]

As it is known that density is the amount of mass of a substance divided by its volume.

So, density of gasoline will be as follows.

                Density = [tex]\frac{mass}{volume}[/tex]

                              = [tex]\frac{595.0 lb}{14.0 ft^{3}}[/tex]

                              = 42.5 [tex]lb/ft^{3}[/tex]

As, 1 lb = 0.4536 kg and 1 ft = 0.3048 m. Now, putting these values into the above equation (1) as follows.

                       Density = 42.5 [tex]lb/ft^{3}[/tex]

                                     = [tex]42.5 \times \frac{0.4536 kg}{(0.3048 m)^{3}}[/tex]

                                     = 680.792 [tex]kg/m^{3}[/tex]    

                                     = 680.8 [tex]kg/m^{3}[/tex] (approx)

Density of water is 1000 [tex]kg/m^{3}[/tex]. To measure specific gravity of gasoline, the formula will be as follows.

               specific gravity of gasoline = [tex]\frac{\text{density of gasoline}}{\text{density of water}}[/tex]    

                                         = [tex]\frac{680.8 kg/m^{3}}{1000 kg/m^{3}}[/tex]

                                         = 0.681

Thus, we can conclude that the specific gravity of gasoline is 0.681.