Respuesta :
Answer: The mass of carbon dioxide produced is 26.9 kg
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of propane = 9 kg = 9000 g (Conversion factor: 1 kg = 1000 g)
Molar mass of propane = 44.1 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of propane}=\frac{9000g}{44.1g/mol}=204.08mol[/tex]
The chemical equation for the combustion of propane follows:
[tex]C_3H_8+5O_2\rightarrow 3CO2+4H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of propane produces 3 moles of carbon dioxide.
So, 204.08 moles of propane will produce = [tex]\frac{3}{1}\times 204.08=612.24mol[/tex] of carbon dioxide.
Now, calculating the mass of carbon dioxide by using equation 1, we get:
Molar mass of carbon dioxide = 44.01 g/mol
Moles of carbon dioxide = 612.24 moles
Putting values in equation 1, we get:
[tex]612.24mol=\frac{\text{Mass of carbon dioxide}}{44.01g/mol}\\\\\text{Mass of carbon dioxide}=(612.24mol\times 44.01g/mol)=26944.7g=26.9kg[/tex]
Hence, the mass of carbon dioxide produced is 26.9 kg
