We have that for the Question "A baseball is popped straight up into the air and has a hang-time of 6.25 S.
Determine the height to which the ball rises before it reaches its peak. (Hint: the time to rise to the peak is one-half the total hang-time.)" it can be said that Hence, the height to which the ball rises before it reaches its peak is
S=47.85m
From the question we are told
A baseball is popped straight up into the air and has a hang-time of 6.25 S.
Determine the height to which the ball rises before it reaches its peak. (Hint: the time to rise to the peak is one-half the total hang-time.)
Generally the Newtons equation for the distance is mathematically given as
[tex]s=ut+1/2at^2\\\\\ Where \\\\T=\frac{6.25}{2}\\\\T=3.125\\\\[/tex]
Therefore
[tex]s=0+1/2(9.8)(3.125)^2[/tex]
S=47.85m
Hence, the height to which the ball rises before it reaches its peak is
S=47.85m
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