On a coordinate plane, a piecewise function has 2 lines. The first line has a closed circle at (negative 4, negative 4) and goes up to an open circle at (negative 1, 2). The second line has a closed circle at (negative 1, 3), continues horizontally to (1, 3), and then goes down to a closed circle at (4, 0).
What is the value of h(3)?

–2
–1
1
2

Respuesta :

Answer:

1

Step-by-step explanation:

The last part of the line starts from (1,3) and goes to (4,0)

We have two points, so we figure out the equation of this line with the formula:

y = mx + b, where m is the slope and b is the y intercept

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m = [tex]\frac{0-3}{4-1}=\frac{-3}{3}=-1[/tex]

So we can now write  y = -x + b

Plugging in a point (1,3), we get:

3 = -1 + b

b = 3+1 = 4

The equation is y = -x + 4

To find h(3), we substitute 3 into x and find the value of y:

y = -x + 4

y = -3 + 4

y = 1

Thus, h(3) = 1

Answer:

c edge2020

Step-by-step explanation: