Respuesta :

Paounn

Answer:

[tex]2.1875 ms^{-2}[/tex]

Explanation:

Newton's second law: [tex]F=ma[/tex] Let's substitute and solve for whatever is left behind:[tex]7.0N= 3.2kg *a[tex]a =\frac {7.0}{3.2} \frac{N}{kg} = 2.1875 \frac{kg\frac{m}{s^2}}{kg}=2.1875 \frac{m}{s^2}[/tex]

snehashish65

The value of acceleration of the airplane is [tex]2.19 \;\rm m/s^{2}[/tex].

Given data:

The mass of propeller model is, m = 3.2 kg.

The net force on the propeller model is,  F = 7.0 N.

Apply the Newton's second law, which says that the applied force on an object is equal to the product of mass of object and acceleration of object, caused due to applied force.

Then the expression is,

[tex]F = m \times a[/tex]

here, a is acceleration.

Solving as,

[tex]7 = 3.2 \times a\\a=2.19 \;\rm m/s^{2}[/tex]

Thus, the required value of acceleration of the propeller model is [tex]2.19 \;\rm m/s^{2}[/tex].

Learn more about the Newton's second law here:

https://brainly.com/question/13447525

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