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16) Kayla's school is selling tickets to the annual dance competition. On the first day of ticket sales
the school sold 6 adult tickets and 8 child tickets for a total of $98. The school took in $70 on the
second day by selling 2 adult tickets and 8 child tickets. Find the price of an adult ticket and the
price of a child ticket.

Respuesta :

calculista

Answer:

The price of an adult ticket is $7 and the price of a child ticket is $7

Step-by-step explanation:

Let

x -----> the price of an adult ticket

y ----> the price of a child ticket

we know that

First day

[tex]6x+8y=98[/tex] -----> equation A

Second day

[tex]2x+8y=70[/tex] ----> equation B

Subtract equation B from equation A and solve for x

[tex]6x+8y=98\\2x+8y=70\\---------\\6x-2x=98-70\\4x=28\\x=7[/tex]

Find the value of y

[tex]2x+8y=70[/tex]

substitute the value of x

[tex]2(7)+8y=70[/tex]

[tex]14+8y=70[/tex]

[tex]8y=70-14[/tex]

[tex]8y=56[/tex]

[tex]y=7[/tex]

therefore

The price of an adult ticket is $7 and the price of a child ticket is $7

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