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caylus
Hello,

Understandable question of a foreigner,

1)
if this means "in the equation ax²+bx+c=0, a=1,b=-3 and c=-5) then the equation is x²-3x-5 (ANSWER A)

2)
if this means "the equation has 1, -3 and -5 as roots " then
the equation is (x-1)(x+3)(x+5)=0
==>x^3+7x²-7x-15=0 (NO ANSWER)

Answer:

Option (a) is correct.

For given values a = 1 , b = -3 , c = -5 the quadratic equation is  [tex]0=-3x-5 + x^2[/tex]

Step-by-step explanation:

Given : a = 1 , b = -3 , c = -5

We have to write the quadratic equation having a = 1 , b = -3 , c = -5 and choose the correct option.

The standard form of quadratic equation is [tex]ax^2+bx+c=0[/tex] , where a, b, c are constant integers.

Given : a = 1 , b = -3 , c = -5

Then Substitute, we get,

[tex]x^2-3x-5=0[/tex]  

Thus, the obtained quadratic equation is same as option (a) [tex]0=-3x-5 + x^2[/tex]

Thus, For given values a = 1 , b = -3 , c = -5 the quadratic equation is[tex]0=-3x-5 + x^2[/tex] 

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