Given the function f(x) = 5x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

Part A: Find the average rate of change of each section. (4 points)
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

Respuesta :

Average rate of change from x = 0 to x = 1 is [tex] \frac{f(1)-f(0)}{1-0}= \frac{5(1)-5(0)}{1}=5 [/tex]
Average rate of change from x = 2 to x = 3 is [tex] \frac{f(3)-f(2)}{3-2}= \frac{5(3)-5(2)}{1}=15-10=5 [/tex]
The average rate of change of both sections are equal.