Respuesta :

whiskeyo
[tex]d=2r\\ A=128 \pi \\ A=2 \pi r^{2} +2 \pi rh \\\\ 2 \pi r^{2} +2 \pi rh = 128 \pi \\ 2 r^{2} +2rh = 128\\ 2 r^{2}+24r-128=0\\ r^{2}+12r-64=0\\ delta=400\\ r_{1/2} = -16/4 \\ r=4cm\\ d=8cm\\ [/tex]

Radius / diameter as a length cannot be negative, that's why '-16' is wrong.

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