Respuesta :
The answer is d.
Explanation:
To start with, classify the first two terms and factor out the common factor. i.e m is a common factor of m2-6m. By factoring it out we get m(m-6).
Follow the same procedure for terms three and four. ie
6 is a common factor of 6m-36. By factoring out, 6(m-6)
Regrouping
m(m-6)+6(m-6)
By factoring out (m-6), we get:
(m-6)(m+6)
Explanation:
To start with, classify the first two terms and factor out the common factor. i.e m is a common factor of m2-6m. By factoring it out we get m(m-6).
Follow the same procedure for terms three and four. ie
6 is a common factor of 6m-36. By factoring out, 6(m-6)
Regrouping
m(m-6)+6(m-6)
By factoring out (m-6), we get:
(m-6)(m+6)
Answer:
Option D [tex](m-6)(m+6)[/tex]
Step-by-step explanation:
we have
[tex]m^{2} -6m+6m-36[/tex]
Simplify
[tex]m^{2} -6m+6m-36=m^{2} -36[/tex]
we know that
In a difference of square
[tex](a^{2}-b^{2})=(a+b)(a-b)[/tex]
Remember that
[tex]36=6^{2}[/tex]
therefore
[tex](m^{2}-6^{2})=(m+6)(m-6)[/tex]