Triangle ABC is similar to Triangle ADE
AB = 2 , BD = 3
AD = 5 , CE = 4
(IT MIGHT HELP TO DRAW A PICTURE, triangle ABC is inside triangle ADE)
I need help solving for AE
I have the basic idea but im not sure if I went about it the right way.......

Respuesta :

If ADE is any triangle and BC is drawn parallel to DE, then AB/BD = AC/CE

To show this is true, draw the line BF parallel to AE to complete a parallelogram 

Triangles ABC and BDF have exactly the same angles and so are similar (Why? See the section called AA on the page How To Find if Triangles are Similar.)

Side AB corresponds to side BD and side AC corresponds to side BF.So AB/BD = AC/BFBut BF = CESo AB/BD = AC/CE
Angle BAD = Angle DAC = x° Angle ADB = y° Angle ADC = (180 - y)°