Respuesta :
All offspring F1 will be dominant for Round seeds ,there will be no recessive wrinkled.
Try punnett square to be sure.
Answer:
The probability of having offspring that have wrinkled seeds and yellow seed color for the cross RRYY ´ RrYy is zero
Explanation:
Given
Round see (R) is dominant to wrinkled seed (r)
While Yellow seed (Y) is dominant to green seed (y)
Now a cross is carried out between RRYY * RrYy, the following offspring are produced
RRYY * RrYy
The gametes of RRYY are RY, RY, RY, RY
The gametes of RrYy are RY, Ry, rY, ry
RY Ry rY ry
RY RRYY RRYy RrYY RrYy
RY RRYY RRYy RrYY RrYy
RY RRYY RRYy RrYY RrYy
RY RRYY RRYy RrYY RrYy
Genotype Ratio
RRYY: RRYy: RrYY: RrYy
4:4:4:4
1:1:1:1
Phenotype
All are round and yellow
The probability of having offspring that have wrinkled seeds and yellow seed color for the cross RRYY ´ RrYy is zero