Respuesta :
A) 3.92 N
In order to model the find the thrust of the rocket, we need to write the equation of the forces acting on it. We have:
- The weight of the rocket, W = mg, acting downward, where m = mass of the rocket and g = acceleration of gravity
- The thurst of the rocket, F, acting upward
The resultant of these forces must be equal to the product between mass and acceleration, so we can write:
[tex]F-mg = ma[/tex]
Where, for the rocket on Earth, we know:
m = 180 g = 0.180 kg is the mass
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
[tex]a=12.0 m/s^2[/tex] is the acceleration of the rocket
Solving for F, we find the thrust:
[tex]F=m(g+a)=(0.180)(9.8+12.0)=3.92 N[/tex]
B) 2.45 N
On the Moon, the situation is exactly the same, but the acceleration of gravity is different:
[tex]g=1.62 m/s^2[/tex]
Then we can use the same equation:
[tex]F-mg = ma[/tex]
where
m = 180 g = 0.180 kg is the mass
[tex]a=12.0 m/s^2[/tex] is the acceleration of the rocket
And solving for F,
[tex]F=m(g+a)=(0.180)(1.62+12.0)=2.45 N[/tex]
The Thrust of the rocket on (A) The earth is 3.924 N (B) The moon is 2.452 N
To calculate the thrust the rocket needs, we use the formula below.
Formula:
- T = mg+ma.................. Equation 1
Where:
- T = Thrust of the rocket
- m = mass of the rocket
- g = acceleration due to gravity
- a = acceleration of the rocket.
(A) On the earth,
Given:
- m = 180 g = 0.18 kg
- a = 12 m/s²
- g = 9.8 m/s²
Substitute these values into equation 1
- T = [(0.18×9.8)+(0.18×12)]
- T = (1.764+2.16)
- T = 3.924 N.
(B) On the moon where g = 1.62 m/s²
Substitute into equation 1
- T = [(0.18×1.62)+(0.18×12)
- T = (0.2916+2.16)
- T = 2.452 N
Hence, The Thrust of the rocket on (A) The earth is 3.924 N (B) The moon is 2.452 N
Learn more about Thrust here: https://brainly.com/question/863770