Answer:
[tex]Zn^0(s)-->Z^{2+}(aq)+2e^{-}[/tex]
Explanation:
Hello,
Considering the stated requirement, such half reaction indicates that pure zinc whose oxidation state is 0 becomes ionized zinc whose oxidation state is 2+; in such a way, its half reaction is:
[tex]Zn^0(s)-->Z^{2+}(aq)+2e^{-}[/tex]
It is important to notice that 2 electrons were transferred since the change in the oxidation state is from 0 to +2:
Best regards.
