Answer:
4.78 × 10²⁴ molecules of NO₂ have 365.2 g
Explanation:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
Given data:
Number of molecules of NO₂ = 4.78 × 10²⁴ molecules
Mass in grams = ?
Solution:
46 g of NO₂ = one mole = 6.022 × 10²³ molecules
46 g/6.022 × 10²³ molecules ×4.78 × 10²⁴ molecules
7.64 g × 10⁻²³ × 4.78 × 10²⁴
365.2 g
4.78 × 10²⁴ molecules of NO₂ have 365.2 g.
