A certain metal with atomic mass 2.2 × 10−25 kg has an interatomic bond with length 2.3 × 10−10 m and stiffness 43 N/m. What is the speed of sound in a rod made of this metal?

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luisafbv93 luisafbv93 · Answer 1 · 2019-10-23T00:54:37+02:00

Answer:

The speed of sound in a rod made of the material is 3215.52 m/s.

Explanation:

The speed of sound can be found using the formula:

[tex]V=\sqrt{\frac{s}{m}}*d[/tex]

Where s is the stiffness, m the atomic mass and d is the length of the interatomic bond.

You just have to correctly replace these values in the formula above.

[tex]V=\sqrt{\frac{43N/m}{2.2 * Exp-25 kg}}*(2.3 * Exp-10 m)[/tex]

V= 3215.52 m/s

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samueladesida43 samueladesida43 · Answer 2 · 2022-03-08T12:52:04+01:00

The speed of the sound in the rod made of this metal is 3215.5m/s

The speed of a sound can be calculated using the following formula:

V = ✓s/m × d

Where;

The speed of the sound can be calculated as follows:

V = ✓43/2.2 × 10−25 × 2.3 × 10−10

V = ✓1.95 × 10²⁶ × 2.3 × 10-¹⁰

V = 1.398 × 10¹³ × 2.3 × 10-¹⁰

V = 3215.5m/s.

Therefore, the speed of the sound in the rod made of this metal is 3215.5m/s.

Learn more about speed of sound at: https://brainly.com/question/15137350