Answer:
A) N2(g)+ 3H2(g) --> 2NH3(g) exothermic
B) S(g) +O2(g) ---> SO2(g) endothermic
C) 2H2O(g) ---->2H2(g) + O2(g) endothermic
D) 2F(g) +F2(g) endothermic
Explanation:
Hello,
By computing the energy difference between the products and reagents for each chemical reaction, one obtains:
A) N2(g)+ 3H2(g) --> 2NH3(g)
ΔrH=2*386 kJ/mol-942 kJ/mol-3*432 kJ/mol=-1466kJ/mol->exothermic
B) S(g) +O2(g) ---> SO2(g)
ΔrH=522 kJ/mol-494 kJ/mol=28kJ/mol->endothermic
C) 2H2O(g) ---->2H2(g) + O2(g)
ΔrH=2*432 kJ/mol+494 kJ/mol-2*459 kJ/mol=440kJ/mol->endothermic
D) 2F(g) --->F2(g)
ΔrH=155kJ/mol>endothermic
Best regards.