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Methane burns in air to produce carbon dioxide and water: CH4(g) + 2 O2(g) --> CO2 (g) +2 H2O (l) What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?

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sebassandin

Answer:

[tex]V=157.91L[/tex]

Explanation:

Hello,

Based on the stoichiometry, the produced moles of carbon dioxide are computed via:

[tex]n_{CO_2}=80.0gCH_4*\frac{1mol CH_4}{16gCH_4} *\frac{1molCO_2}{1molCH_4}=5mol CO_2[/tex]

Now, by using the ideal gas law and subsequently solving for the volume we get:

[tex]V=\frac{nRT}{P}= \frac{5mol*0.082\frac{atm*L}{mol*K}*385.15K}{1atm}=157.91L[/tex]

Best regards.