A 161-kg block is pulled at a constant speed of 7.40 m/s across a horizontal floor by an applied force of 138 N directed 36° above the horizontal. What is the rate at which the force does work on the block?

Respuesta :

Answer:

510.6 W

Explanation:

The rate at which the force does work is called power therefore it is given by:

[tex]P=\frac{\Delta W}{\Delta t}[/tex]

The instantaneous power applied on a rigid solid is given by the product of the constant force applied over the solid's velocity.

[tex]P=F\cdot v\\P=Fvcos\theta[/tex]

Here [tex]\theta[/tex] is the angle between the force and the velocity.

[tex]P=138N(7.4\frac{m}{s})cos(36^\circ)\\P=510.6W[/tex]