The specific heat of water is 4.18 J/(g * °C) How much heat, in kilojoules, must be added to 250 g of water to increase the temperature of the water by 5.0°C?
You need to use the equation q=mcΔT. q=the heat absorbed or released m= the mass of the sample (in this case 250g) c=the specific heat of the sample (in this case 4.18J/g°C) ΔT=the change in temperature (in this case 5°C) When you plug every thing in you should get q=5225J or 5.225kJ
I hope this helps. Let me know if anything is unclear.
