Answer:
2
Step-by-step explanation:
Let's change the base to base 10 (log10(x) = log(x)).
logb(a) = log(a)/log(b)
log3(3²) =log(3²)/log3
Knowing that log(aⁿ) = n*log(a)
log(3²)/log3 = 2*log(3)/log(3)
So, we can simply log(3)/log(3) = 1
log3(3²) = 2