Answer:
A = [tex]\dfrac{1}{16}\begin{bmatrix}a &-(a-4) \\ -(a+4) & a\end{bmatrix}[/tex]
Step-by-step explanation:
given,
Matrix =
A = [tex]\begin{bmatrix}a &a-4 \\ a+4 & a\end{bmatrix}[/tex]
determinant of matrix
|A| = a×a - (a-4)(a+4)
|A| = a² - a² +16
|A| = 16
inverse of the matrix
to calculate inverse of two matrix interchange the term a₁₁ with a₂₂ and multiply the -ve with a₁₂ and a₂₁
the inverse is
A = [tex]\dfrac{1}{16}\begin{bmatrix}a &-(a-4) \\ -(a+4) & a\end{bmatrix}[/tex]
