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Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the charge on each electrode and the potential difference between them?

Respuesta :

davidlcastiblanco

Answer:

The charge on each electrode is

[tex]q=0.354 x10^{-12}[/tex]

Explanation:

The charge to find the equation is development

V=9v

[tex]d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )[/tex]

[tex]q=C*V[/tex]

[tex]C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4}  }{0.01}=0.354  \\[/tex]

[tex]q=0.354*9v\\q=3.186x10^{-12} C[/tex]

okpalawalter8

The charge on each electrode and the potential difference between them is mathematically given as

q=3.186x10^{-12} C

What is the charge on each electrode and the potential difference between them?

Question Parameter(s):

Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery

Generally, the equation for the charge  is mathematically given as

q=C*V

Where

[tex]C=\frac{E_{o}*A }{d} \\\\C=\frac{8.85x10^{-12} *4x10^{-4} }{0.01}[/tex]

C=0.354  

In conclusion, The charge

q=0.354*9v

q=3.186x10^{-12} C

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