Answer
a) (4, −9) and (1, −5)
distance between two points
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]D = \sqrt{(1-4)^2+(-5-(-9))^2}[/tex]
[tex]D = \sqrt{9+16}[/tex]
D = 5
b) 4 − 9 i and 1 − 5 i
r = (4-1) + (-9 -(-5))i
r = 3 - 4 i
[tex]D = \sqrt{3^2 + 4^2}[/tex]
[tex]D = \sqrt{3^2 + 4^2}[/tex]
[tex]D = \sqrt{9+16}[/tex]
[tex]D = \sqrt{25}[/tex]
D = 5
c) both the result are numerically same because complex number represent point on the graph where y -axis represent imaginary axis and x -axis is real value axis.
