A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is the girl's tangential speed?

Respuesta :

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with uniform circular motion, her centripetal acceleration [tex]a_{c}[/tex] is given by the following equation:  

[tex]a_{c}=\frac{V^{2}}{r}[/tex] (1)

Where:  

[tex]a_{c}=17 m/s^{2}[/tex] is the centripetal acceleration

[tex]V[/tex] is the tangential speed

[tex]r=12 m[/tex] is the radius of the circle

Isolating [tex]V[/tex] from (1):

[tex]V=\sqrt{a_{c}r}[/tex] (2)

[tex]V=\sqrt{(17 m/s^{2})(12 m)}[/tex]

Finally:

[tex]V=14.28 m/s[/tex] This is the girl's tangential speed