Answer:
12 liters of pure acid with 24 liters of 10% acid solution
Step-by-step explanation:
Let us assume that x liters of pure acid is mixed with y liters of 10% acis solution.
Therefore, x+y =36 liters ....... (1)
Again the resulting acis solution is of 40% concentration.
Hence, [tex]\frac{x+0.1 y}{x+y}=\frac{40}{100}=0.4[/tex]
⇒ x+0.1y =0.4x +0.4y
⇒ 0.6x =0.3y
⇒ 2x =y .....(2)
Now, solving equations (1) and (2) we get,
3x =36, ⇒ x= 12 liters
And, from equation (2), we get y=2×12 =24 liters.
Therefore, the technician has to mix 12 liters of pure acid with 24 liters of 10% acid solution to get the requires solution. (Answer)