Answer:
[tex]0.240 J/(g^{\circ}C)[/tex]
Explanation:
When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex] according to the equation
[tex]Q=mC_s \Delta T[/tex]
where
[tex]C_s[/tex] is the specific heat capacity of the substance
In this problem, we have:
m = 55.0 g is the mass of the sample of silver
[tex]Q = 47.3 \cdot 4.184 = 197.9 J[/tex] is the amount of energy supplied to the sample
[tex]\Delta T = 15^{\circ}C[/tex] is the change in temperature of the sample
Solving the equation for [tex]C_s[/tex], we find the specific heat capacity of silver:
[tex]C_s = \frac{Q}{m \Delta T}=\frac{197.9}{(55.0)(15)}=0.240 J/(g^{\circ}C)[/tex]
