If KL bisects JLM, find
the values of x and y below,
570
(8y)"
370
(7x + 1)º

Answer:
6=x
5.375=y
Step-by-step explanation:
You add 57° and 37° together and get 94°
You subtract the 94° from 180° (the total of the angles for all triangles) and you get 86°.
So the third angle is 86°, but it is bisected, so you divide it in half.
43=7x+1
You subtract one from both sides, giving you 42=7x
you divide 42 by 7 and get 6, so x is 6.
You divide 8 by 43 to get y.
Answer:
y = 10 degrees
x = 6 degrees
Step-by-step explanation:
The question here is to know the degrees of x and y
From the triangle JLM, we already knew the angles of ∠LJM = 57 and ∠JML = 37, so we need to find out the angle of ∠JLM.
Use the properties of a triangle that the sum of the 3 angles are 180 degrees.
So we have:
<=> ∠JLM = 180 - 57 - 37 = 86 degrees
However, ∠JLM = 2 ∠KLM because KL bisects JLM
<=> 86 = 2 (7x+1)
<=> x = 6 degrees
<=> ∠KLM = 43 degrees
<=> ∠KLJ = 43 degrees
From the triangle JKL, we already knew the angles of ∠KLJ = 43 and ∠LJM = 57. So once again, we use the properties of a triangle that the sum of the 3 angles are 180 degrees.
<=> ∠LKM = 180 - ∠KLJ - ∠LJM
<=> ∠LKM = 180 - 43 - 57 = 80
<=> 8y = 80
<=> y = 10 degrees