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two winners are to share a prize of $750. If one winner receives twice as much as the other, how much will they each receive?​

Respuesta :

adeshmakwana203

Answer: winner 1 : 500

Winner 2 : 250

Step-by-step explanation:

Consider both winners share as 'x' and winner 1 will get the prize share twice than winner 2's share

2x+x = 750 ---------- eq. 1

3x= 750

x=750/3

x = 250

Put the value of 'x' in eq.1

2(250)+(250) =750

500+250=750

varshamittal029

One of them will receive $250 and the other one will receive $500 .

What is the algebraic equation?

An algebraic equation is a mathematical statement that equalizes two expressions.

Example - 4x + 6 = 2x + 2.

How to solve this problem?

Given that the total amount of the prize is $750 and one winner receives twice as much as the other. Let one receives the amount $x. Then the other will receive the amount $2x. Then the required algebraic equation is x + 2x = 750.

We have to solve this algebraic equation to get the desired result.

Now, x + 2x = 750

i.e. 3x = 750

i.e. x = 750/3 =250

Hence one of them will receive $250 and the other one will receive $250*2 = $500.

Know more about algebraic equations here -

https://brainly.com/question/953809

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