The x - component of the velocity is 13 m/s
The given parameters include;
The magnitude of the velocity is calculate as;
[tex]v_y = v\ sin(\theta )\\\\v = \frac{v_y}{sin(\theta)} = \frac{13}{sin(45)} = 18.38 \ m/s[/tex]
The x - component of the velocity is calculated as follows;
[tex]v_x = vcos (\theta )[/tex]
vₓ = 18.38 x cos(45)
vₓ = 18.38 x 0.7071
vₓ = 13 m/s
Thus, we can conclude that at an angle 45⁰ the slope of the line is 1 and the y component of the velocity and x component of the velocity will be equal.
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