Respuesta :
Answer:
(0,1) is the unique solution of the system .
Step-by-step explanation:
The given sets of equations are
x + 2y = 2
x - 2y = -2
Compare the equations with ax + by = c
Here, we get a1 = 1, b1 = 2 and c1 = 2
and a2 = 1, b2 = -2 and c2 = -2
Now, as we can see , [tex]\frac{a1}{a2} = \frac{1}{1}, \frac{b1}{b2} =\frac{2}{-2} = -1 , \frac{c1}{c2} = \frac{2}{-2} =-1[/tex]
Here, [tex]\frac{a1}{a2} \neq \frac{b1}{b2}[/tex]
Hence, the system has UNIQUE SOLUTION.
And, (0,1) is the unique solution of the system
x + 2y = 0 + 2(1) = 2 = Right side
and x - 2y = 0 - 2(1) = -2 = Right side
Answer: It has one solution (0, 1).
Step-by-step explanation:
x+2y=2
x-2y=-2
This equation can be solve by either substitution method or by elimination method or both method
We shall use the two method to solve this equations
x+2y=2 ----------------(1)
x-2y=-2-----------------(2)
To eliminate x, I will simply subtract equation (2) from equation (1)
(x-x=0 2y -[-2y] = 4y 2-[-2]=4)
The equation becomes;
4y = 4
So to get the value of y, we will simply divide both-side of the equation by 4
4y/4 = 4/4
y = 1
substitute y=1 to any of the equation, either equation (1) or equation (2)
Lets substitute y=1 in equation (1)
x+2y=2
x + 2(1) =2
x + 2 = 2
To get the value of x, we will simply subtract 2 from both-side
x + 2 - 2 = 2-2
x = 0
Therefore the solution of these equations is;
x=0 and y=1
(0,1)
Hence, the system of equations has one solution which is (0, 1)
