Answer:
0.81549 m
Explanation:
t = Time taken by the diver
u = Initial velocity of the diver = 4 m/s
v = Final velocity of the diver
s = Displacement of the diver
a = Acceleration due to gravity = 9.81 m/s²
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-4^2}{2\times -9.81}\\\Rightarrow s=0.81549\ m[/tex]
a) Her highest height above the board is 0.81549 m
