The price of Stock A at 9 A.M. was ​$13.14. Since​ then, the price has been increasing at the rate of ​$0.06 each hour. At noon the price of Stock B was ​$13.64. It begins to decrease at the rate of ​$0.09 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

Respuesta :

Answer:

[tex]2\frac{2}{15}[/tex] hours from noon the stock prices will be same

Step-by-step explanation:

We can write equations for increasing stock and decreasing stock and find our answer.

Let number of hours be "t" for both to be same

For first, we can write:

13.14 + 0.06t

But, 2nd one starts from noon, so already 12pm - 9am = 3 hours gone, so stock A increased by 3 * 0.06 = 0.18, so we equation would be:

13.32 + 0.06t

Now, Stock B's equation [from noon]:

13.64 - 0.09t

Equate and solve:

[tex]13.32 + 0.06t=13.64-0.09t\\0.15t=0.32\\t=2\frac{2}{15}[/tex]

In 2  2/15 hours, the prices will be same