Answer:
Speed: 4.8 m/s
Velocity: 4.8 m/s north
Explanation:
Definitions:
- Speed is a scalar quantity, which is equal to the ratio between distance covered (d) and time taken (t):
[tex]s=\frac{d}{t}[/tex]
- Velocity is a vector quantity, whose magnitude is equal to the ratio between the displacement of the object and the time taken:
[tex]v=\frac{disp.}{t}[/tex]
And it also has a direction (the same as the displacement).
In this problem:
- The object travels a distance of
d = 105 m
In a time interval of
t = 22 s
So its speed is
[tex]s=\frac{105}{22}=4.8 m/s[/tex]
- The displacement of the object is the same as the distance in this case, so still 105 m, covered in a time interval of 22 s; this means that the magnitude of the velocity is the same as the speed:
[tex]v=4.8 m/s[/tex]
However, velocity is a vector quantity, so it also has a direction: and since the object has moved north, the direction of the velocity is north as well.
