Respuesta :
Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a = [tex]\dfrac{13060.96}{M}[/tex]
a= [tex]\dfrac{13060.96}{4410}[/tex]
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
Answer:
4457.7 N
Explanation:
87g = 0.087kg
v = 853m/s
t = 2.93 s
total mass hitting = m = 0.087*176 = 15.32 kg
net momentum = mv = 15.32*853 = 13061 kg.m/s
as we know the rate of change of momentum is the average force of impact,
F_avg = [tex]\frac{mv}{t}[/tex] = [tex]\frac{13061}{2.93}[/tex] = 4457.7 kg.m/s^2 = 4457.7 N
