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An unknown hydrocarbon A with the formula C7H14 reacts with 1 molar equivalent of H2 over a palladium catalyst to give hydrocarbon B. Hydrocarbon A also reacts with OsO4 to give diol C. Treatment of diol C with periodic acid gives ketone D and aldehyde E. When oxidized with KMnO4 in acidic solution, A gives two fragments. One fragment is propionic acid, CH3CH2CO2H, and the other fragment is ketone D. Draw the structure of compound D.

Respuesta :

Answer:

D is 2-butanone.

Explanation:

  • The hydrocarbon A should contain a trisubstituted double bond as it gives an acid and a ketone on treatment with [tex]KMnO_{4}[/tex].
  • The hydrocarbon A should contain only one double bond as it reacts with 1 molar equivalent of [tex]H_{2}[/tex] over palladium.
  • The hydrocarbon A contains seven carbon atom. Therefore the ketone D should contain 4 carbon atoms as propionic acid ( 3 carbon atom) is produced as another fragment.
  • Reaction and structure of D has been shown below.
Ver imagen OrethaWilkison

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