Answer:
[tex]a=0.4m/s^2[/tex]
Explanation:
The formula for calculating acceleration is as follows:
[tex]a=\frac{v_{f}-v_{i}}{t}[/tex]
where [tex]v_{f}[/tex] is the final velocity, [tex]v_{i}[/tex] the initial velocity, an [tex]t[/tex] is the time in wich the velocity changed.
For this case:
[tex]v_{f}=6m/s[/tex]
[tex]v_{i}=4m/s[/tex]
[tex]t=5s[/tex]
Thus the acceleration is:
[tex]a=\frac{6m/s-4m/s}{5s}[/tex]
[tex]a=\frac{2m/s}{5s}[/tex]
[tex]a=0.4m/s^2[/tex]
The acceleration of Josh is: [tex]a=0.4m/s^2[/tex]
The acceleration of Josh is 0.4 m/s²
The given parameters;
The acceleration of Josh is calculated as follows;
[tex]a = \frac{v- u}{t}[/tex]
where;
a is the acceleration
Substitute the given values of the velocities and calculate the magnitude of the acceleration;
[tex]a = \frac{6-4}{5} \\\\a = 0.4 \ m/s^2[/tex]
Thus, the acceleration of Josh is 0.4 m/s²
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