A person eats a dessert that contains 230 Calories. (This "Calorie" unit, with a capital C, is the one used by nutritionists; 1 Calorie = 4186 J.) The skin temperature of this individual is 36°C and that of her environment is 17° C. The emissivity of her skin is 0.75 and its surface area is 1.3 m2. How much time would it take for her to emit a net radiant energy from her body that is equal to the energy contained in this dessert?

Respuesta :

Explanation:

Calories are the amount of energy stored in food and are the specific amount of energy required to reuse a kilogram of water by 1°C. These calories within food are obtained from nutrients in food which have been converted into energy molecules called ATP. This is essential, and is produced through several complex pathways in the body during the process of cellular respiration and is crucial to survival of cells, tissues, organs and organisms.

Converting the provided temperatures to absolute temperatures:

[tex]t= \frac{Q}{P net}[/tex]

[tex]t= \frac{Q}{eoA ( T^{4}  -T_{0} ^{4}} )[/tex]

where...

[tex]  Q= 260 Calories(\frac{ ( 4186 J)}{ 1 Calorie}[/tex]

                  [tex]T[/tex]= 36 °C + 273= 309 K

                  [tex]T_{0}[/tex]17  °C + 273= 290 K

ΔT=[tex]T^{4} - T_{0}^{4}[/tex] = 1.645 x 10^9 K^4

[tex]t= \frac{260 Calories(\frac{ ( 4186 J)}{ 1 Calorie}} {(0.75) [5.67 x 10^-8 J/ (s.m^2. K^2)](1.3m^2) ( 2.043^9 K^4)}[/tex]

[tex]t= 9.636 * 10^{3}[/tex] seconds (time taken for her to emit a net radiant energy equal to the energy in the dessert)

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