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Ariel dropped a golf ball from her second story window the ball starts from rest and hits the sidewalk 1.5 seconds later with a velocity of 14.7 m/s find the average acceleration of the golf ball

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mberisso

Answer:

Average acceleration: [tex]9.8 \frac{m}{s^2}[/tex]

Explanation:

Use the formula for average acceleration: [tex]a=\frac{v_f-v_1}{t} \\a=\frac{14.7-0}{1.5}\\a=9.8 \frac{m}{s^2}[/tex]

nuhulawal20

The average acceleration of the golf ball as it was dropped from the second story window is 9.8m/s².

Given the data in the question;

Since the ball started from rest

  • Initial velocity; [tex]u = 0m/s[/tex]
  • Final velocity; [tex]v = 14.7m/s[/tex]
  • Time taken for the golf ball to hit the sidewalk; [tex]t = 1.5s[/tex]
  • Average Acceleration; [tex]g = \ ?[/tex]

To determine the average acceleration of the golf ball, we use the First Equation of Motion:

[tex]v = u + at[/tex]

Where v is the final velocity, u is the initial velocity, t is the time and a is the acceleration. Since the ball was dropped from a certain height ( story wind ), it is under gravity and acceleration due to gravity.  

Hence, the equation becomes;

[tex]v = u + gt[/tex]

We substitute our given values into the equation and find "g"

[tex]14.7m/s = 0m/s + ( 1.5s\ *\ g )\\\\g = \frac{14.7m/s}{1.5s}\\\\g = 9.8m/s^2[/tex]

Therefore, the average acceleration of the golf ball as it was dropped from the second story window is 9.8m/s².

Learn more; https://brainly.com/question/7287760

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