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Consider the following cyclic process carried out in two steps on a gas. Step 1: 44 J of heat is added to the gas, and 20. J of expansion work is performed. Step 2: 61 J of heat is removed from the gas as the gas is compressed back to the initial state. Calculate the work for the gas compression in Step 2.

Respuesta :

Answer:37 J

Explanation:

Given

Step :1

Heat added Q=44 J

Work done=-20 J

[tex]\Delta E_1=Q+W=44-20=24 J[/tex]

Step :2

Heat added Q=-61 J

work done [tex]W_2[/tex]

[tex]\Delta E_2=Q+W_2[/tex]

[tex]\Delta E_2=61+W_2[/tex]

[tex]\Delta E_1+\Delta E_2=0[/tex]

as the process is cyclic

[tex]44-20-61+W_2=0[/tex]

[tex]W_2=37 J[/tex]

work done in compression is 37 J

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