Answer:
Step-by-step explanation:
Urn 1
5 red, 3 blue
Urn 2
7 red, 3 blue
When a marble is selected at random from urn 1,
P(red) = [tex]\frac{5}{8} =0.625[/tex]
P(blue) = [tex]1-0.625\\=0.375[/tex]
When red is drawn p of drawing red from second urn = [tex]\frac{8}{11}[/tex]
Otherwise p of drawing red from second urn=[tex]\frac{7}{11}[/tex]
a) the probability that the marble drawn from Urn 2 is red
= [tex]\frac{8}{11} *\frac{5}{8} +\frac{7}{11} *\frac{3}{8} \\=\frac{61}{88}[/tex]
b) the conditional probability that the ball drawn from Urn 1 is red, given that a blue marble is drawn from Urn 2
= prob from urn 2/answer for a
=[tex]\frac{21}{88} /\frac{61}{88} \\=\frac{21}{61}[/tex]
