Answer:
The corner of the base is 705.72 feet from the top of the pyramid
Step-by-step explanation:
we know that
In a right triangle we can apply the Pythagorean Theorem to find out the length of the hypotenuse
[tex]c^{2}=a^2+b^2[/tex]
where
c is the hypotenuse
a and b are the legs of the right triangle (perpendicular sides)
In this problem we have
[tex]a=604\ ft\\b=365\ ft[/tex]
substitute
[tex]c^{2}=604^2+365^2[/tex]
[tex]c^{2}=498,041[/tex]
[tex]c=705.72\ ft[/tex]
therefore
The corner of the base is 705.72 feet from the top of the pyramid
