Energy is required to move a 657 kg mass from the Earth’s surface to an altitude 2.97 times the Earth’s radius RE. What amount of energy is required to accomplish this move? The acceleration of gravity near the Earth is9.8 m/s 2 , the mass of the Earth is 5.98 × 1024 kg , and the radius of the Earth is 6.37 × 106 m . Answer in units of J.

Respuesta :

Answer:

 U = - 1,385 10¹⁰ J

Explanation:

To calculate the energy of that movement we can use the expression for gravitational potential energy, derived from the law of universal gravitation

            U = - G m1 M / r

Where zero is taken at an infinite distance

We can substitute and calculate

              r = 2.97 Re

             U = - 6.67 10⁻¹¹ 5.98 10²⁴ 657 /(2.97 6.37 10⁶)

             U = - 1,385 10¹⁰ J

This is a very large energy value.

Gravitation is a natural law by which all things with all matter are attracted towards one another. The amount of energy is required to accomplish this move will be 6458.2 J

What is gravity?

Gravitation is a natural law by which all things with all matter are attracted towards one another. Gravity causes weight to all matter and the gravity of the moon causes the ocean tides.

The given data in the problem is;

m is the mass to be moved=657 Kg

h is the altitude = 2.97 radius of the earth

E is the amount of energy=?

g is the acceleration of gravity near the Earth = 9.8 m/s²

M is the mass of earth = 5.98 × 10²⁴ kg

R is the radius of the earth= 6.37 × 10⁶ m.

The formula for the gravitational potential energy is given by;

[tex]\rm U=G\frac{mM}{R^2} \\\\ \rm U=\frac{6.67 \times 10^{-11}\times 675 \times 5.98 \times 10^{24}}{(2.97 \times 6.37\times10^6)^2} \\\\ \rm U=6458.2 N[/tex]

Hence the amount of energy is required to accomplish this move will be 6458.2 J

To learn more about gravity refer to the link;

https://brainly.com/question/1479537