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Find the product of 3 and the linear equation, and solve for both equations for y.
2y-4x=8
The product of 3 and 2y-4x=8 is ______
The original equation in slope intercept form is y=________
The new equation in slope intercept form is______

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calculista

Answer:

Part 1) The product of 3 and 2y-4x=8 is [tex]6y-12x=24[/tex]

Part 2) The original equation in slope intercept form is [tex]y=2x+4[/tex]

Part 3) The new equation in slope intercept form is [tex]y=2x+4[/tex]

Step-by-step explanation:

we have

[tex]2y-4x=8[/tex]

step 1

Find out the product of 3 and 2y-4x=8

Multiply both sides by 3

[tex]3(2y-4x)=3(8)[/tex]

Apply distributive property both sides

[tex]6y-12x=24[/tex]

step 2

Find out the original equation in slope intercept form

The equation of the line in slope intercept form is

[tex]y=mx+b[/tex]

we have

[tex]2y-4x=8[/tex]

Solve for y

That means ----> Isolate the variable y

Adds 4x both sides

[tex]2y=4x+8[/tex]

Divide by 2 both sides

[tex]y=(4x+8)/2[/tex]

Simplify

[tex]y=2x+4[/tex]

step 3

Find out the new equation in slope intercept form

The equation of the line in slope intercept form is

[tex]y=mx+b[/tex]

we have

[tex]6y-12x=24[/tex]

Solve for y

That means ----> Isolate the variable y

Adds 12x both sides

[tex]6y=12x+24[/tex]

Divide by 6 both sides

[tex]y=(12x+24)/6[/tex]

Simplify

[tex]y=2x+4[/tex]

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