Answer:
[tex]4.98\cdot 10^{-19} J[/tex]
Explanation:
The energy of the emitted photon is inversely proportional to its wavelength, according to the equation:
[tex]E=\frac{hc}{\lambda}[/tex]
where
[tex]h=6.63\cdot 10^{-34} Js[/tex] is the Planck's constant
[tex]c=3.0\cdot 10^8 m/s[/tex] is the speed of light
[tex]\lambda[/tex] is the wavelength
This means that the biggest energy is released when the wavelength is the shortest. For a photon of visible light, the shortest wavelength is
[tex]\lambda=400 nm = 400\cdot 10^{-9} m[/tex]
So, substituting into the equation, we find the corresponding energy:
[tex]E=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{400\cdot 10^{-9}}=4.98\cdot 10^{-19} J[/tex]
