Answer:
5 units to right and 23 units down
Step-by-step explanation:
The vertex of [tex]f(x)=x^{2}[/tex] is at [tex](0,0)[/tex].
In order to find the vertex of function a(x), we convert the function a(x) to vertex form.
The general vertex form is [tex]y=a(x-h)^{2} +k[/tex].
Here, [tex](h,k)[/tex] is the vertex.
[tex]a(x)=x^{2} -10x+2\\ a(x)=(x-5)^{2}-25+2=(x-5)^{2}-23[/tex]
So, the vertex of the graph of a(x) is at [tex](5,-23)[/tex] and the vertex of f(x) is at [tex](0,0)[/tex].
Therefore, in order to translate [tex](0,0)[/tex] to [tex](5,-23)[/tex], we have to move the vertex of f(x) 5 units to right and then 23 units down.
